16b^2-8b-15=0

Solution for 16b^2-8b-15=0 equation:

16b^2-8b-15=0

a = 16; b = -8; c = -15;
Δ = b2-4ac
Δ = -82-4·16·(-15)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-32}{2*16}=\frac{-24}{32}
=-3/4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+32}{2*16}=\frac{40}{32}
=1+1/4
$